3*0.2^(3x)+0.008^(x+1/3)=16

Solution for 3*0.2^(3x)+0.008^(x+1/3)=16 equation:

3*0.2^(3x)+0.008^(x+1/3)=16

We move all terms to the left:

3*0.2^(3x)+0.008^(x+1/3)-(16)=0

We add all the numbers together, and all the variables

3*0.2^3x+0.008^(+x+1/3)-16=0

Wy multiply elements

0x+0.008^(+x+1/3)-16=0

We multiply all the terms by the denominator


0x*3)+0.008^(+x+1-16*3)=0

We add all the numbers together, and all the variables

0x*3)+0.008^(x-47)=0

We add all the numbers together, and all the variables

0x*3)+0.008^(x=0

Wy multiply elements

0x^2=0

We add all the numbers together, and all the variables

x^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{2}=0$